Question

4. Find V, from following circuit using Norton's theorem only. 12V 2 ΚΩ 3 mA 4 ΚΩ 12 ΚΩ 4 ΚΩ

Answer 1

2k2 12V Solutions 3MA 8462 Vo To find lo using Norton theorom we have to find I Norton equivalent Cussent and Morton sesistance. 12K2 Vo= R © Step 1 : To find Morton equivalent Resistance RN, open circuit all cussent source and short circuit all Hollage Sousse, and Remove to resistance. 2k s-e RN (2+4) || 12 + 24K RN 6612 312k 6 +12 RN = 4k Step2. To find Morton Cusscut, shost Cisuit Vo sesistance 2K 12V 12V I Voltage sousce connecting into equinalent Cussent source. now, Ciruit becomes YIN=(1,- I2) 3MA 34k §12K I-V- = 4 12 12k = 1mA 2K 12 3MA YIN Note :- Cussent alevays flow from low sesistance. path. If a short circuit across any value of sesistance the total cussent will flow through that short circuit. इ4k Z12k 1 IMA Morton Cussent IN = Iz-I, IN ImA - 3 MAX 4k 4K 72k IN = Ima - 2 mA IN =-1 mA cussent flow in opposite Negative value means Voltage Vo from the Morton equivalent parametes direction. Vo = FERN InxReq = IN RNXYK 4K+RN IN E IMA ERN =4K + Ho 4k Vo =-1x 4K x 4k 4k+uk Vo = -1MAX 2k 9 Vo =-2v >

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