Consider the circuit diagram with the solution uploaded below .
Here i2=6mA because of the 6mA current source.
I3 =-2mA because of the 2mA current source which is pointing in the opposite direction in which we are traversing loop 3.
we don't need to find i1 ,but I'm simply writing that for your reference.
Chapter 3, Problem 3.091 (Circuit Solution) Find Io in the circuit in the figure using mesh analysis. 1V (H ΚΩ 34 ΚΩ 3 mA 2 kΩ _22 6 ΚΩ ΚΑΙ 1 mA S2 ΚΩ Io = mA
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Find V. in the circuit in the figure below using superposition. =3 mA 7 kΩ Ο 4 kg 7 kΩ Ta = 2V I h = 8V 4 ΚΩ 6 kΩ Ι ο Vo with only V, turned on Vo with only V6 turned on 75.6 V with only I, on = V =
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Using mesh analysis, find Vo in the circuit in the figure. 4000 6 mA
Find Io in the circuit using mesh current analysis. 6 ΚΩs 12V 36 ΚΩ 6 ΚΩ ΛΙ 6 ΚΩ 6 mm 0 312K2 0 4 ma
Find V, from following circuit using Thevenin's theorem. 3 ΚΩ 6 kΩ 3 kΩ 4 mA 12V 12 V
Please solve using Norton, Ans: -2V 4. Find Vo from following circuit using Norton's theorem only. 12V 2 ΚΩ 3 mA 4 kΩ 4 kΩ V. 12 kΩ
Chapter 3, Problem 3.108 Use mesh analysis to find V, in the circuit in the figure. 7 mA 8 k 2 +6 12k12 Vx 3 12 k22 4 k22 di o Vo = the tolerance is +/-5% Click if you would like to Show Work for this question: none
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