Question

Chapter 3, Problem 3.108 Use mesh analysis to find V, in the circuit in the figure. 7 mA 8 k 2 +6 12k12 Vx 3 12 k22 4 k22 di o Vo = the tolerance is +/-5% Click if you would like to Show Work for this question: none

Answer 1

3. 108) Given Circuit 12K- 12KL Asume Mesh currents 1, 2 & Iz for Meshes, 243 respectively -> Here 7 mA curent source foms Supermesh Apply KVL for Mesh) (rak) I, +(8k) (1,-1,-) + 4k(1,-1) = 0 Q4K) I, -8%) 12-14k) I2 = 0 61-212-Iz o Apply KVL for Mesh 2 & Mesh 3 combinely (ak)24+ 7 VX + (8k) (9.-21) 4(45) 13-11) = 0 (2K) I, +(8K)12+(16k) = -7 VX from Circuit Vm= 14k) (1,-13) (2K)1, +4K)12+(6k) Iz = -7(4K) (9,-1) -(126)1, +48 K) 1, +(8K) 1 + 6K) IZ-28K)T=0 16k) 1, +(8K) Ix-(2k) 1,20 41, +2 Iz~3I3=0 →

By Solving , & I = 9.33 mA I = 16. 33 mA Iz = 23.33mA Vo = Voltage across 12K2 Virker = (12K) Iz Viske = (lak)(23.33 m) = 279-96v Vo = 279.96v