Find v, in the given circuit where P = 90 sin(2t) V. Please report your answer...
Find Voin the given circuit where P = 120 sin(21) V. Please report your answer so the magnitude is positive and all angles are in the range of negative 180 degrees to positive 180 degrees. 0.5 H + Р +1 2H ele ell 2 H vo 0.5 F The value of vo(t) = cos(2t+ 1).
Need help. Find Voin the given circuit where P = 120 sin(21) V. Please report your answer so the magnitude is positive and all angles are in the range of negative 180 degrees to positive 180 degrees. 0.5 H . . + P 2H ele 2 H vo 0.5 F The value of volt) cos(2t + ]. V.
Find v(t) for the given circuit, where R-8 Ω and VS-155 sin (3) V. Please report your answer so the magnitude is positive and all angles are in the range of negative 180 degrees to positive 180 degrees. 2Ω 12 The value of voltage v(t) sin(3t+ V.
Using the superposition principle, find it in the circuit given below, where R=6 . Please report your answer so the magnitude is positive and all angles are in the range of negative 180 degrees to positive 180 degrees. F ix 10 cos(2t + 109) A ( 20cos(2t -60°) V The component of the current due to the voltage source is is ) A. cos(2+0 COS(2+ The component of the current due to the current source is 12 )) A The...
Calculate the output current in the circuit given below, where / = 121. Please report your answer so the magnitude is positive and all angles are in the range of negative 180 degrees to positive 180 degrees. 2 ko 2uF 25 cos(4 X 103t) V + 0.25 H The output current in the circuit is io(t) = cos(4 x 103t + °) ma.
Find Vx in the network shown in the given figure, where P = 8<50° V. Please report your answer so the magnitude is positive and all angles are in the range of negative 180 degrees to positive 180 degrees. Find V, in the network shown in the given figure, where P = 8/50° V. Please report your answer so the magnitude is positive and all angles are in the range of negative 180 degrees to positive 180 degrees. j1Ω 2...
Find Vy in the network shown in the given figure, where P = 10240° V. Please report your answer so the magnitude is positive and all angles are in the range of negative 180 degrees to positive 180 degrees. j1Ω 2Ω 2Ω + V P j4 Ω j4 Ω -j1Ω 2/0° A The value of VX V.
Find the Norton equivalent for the given circuit at terminals a-b. Given -2 A. Please report your answer so the magnitude is positive and all angles are in the range of negative 180 degrees to positive 180 degrees 10Ω /10 Ω ! Norton's equivalent current IN Norton's equivalent impedance Zeq Find the Norton equivalent for the given circuit at terminals a-b. Given -2 A. Please report your answer so the magnitude is positive and all angles are in the range...
Find Vx in the network shown in the given figure, where P = 8 < 40° V. Please report your answer so the magnitude is positive and all angles are in the range of negative 180 degrees to positive 180 degrees. Find Vy in the network shown in the given figure, where P = 8240° V. Please report your answer so the magnitude is positive and all angles are in the range of negative 180 degrees to positive 180 degrees....
For the given circuit, determine the values of V, and I where A = 6020° V. Please report your answer so the magnitude is positive and all angles are in the range of negative 180 degrees to positive 180 degrees. j5 Ω + 12 + Vi j102 j10 2 A 1020° A The value of 12 = + A and V1 1. V.