Question

Find Vx in the network shown in the given figure, where P = 8 < 40° V. Please report your answer so the magnitude is positive and all angles are in the range of negative 180 degrees to positive 180 degrees.

Find Vy in the network shown in the given figure, where P = 8240° V. Please report your answer so the magnitude is positive and all angles are in the range of negative 180 degrees to positive 180 degrees. j1 Ω 22 222 w www + V P+ 340 E 3402 -j1 2 12 X0° A . The value of VX V. MacBook Pro

Answer 1

Given Information: jir rt 22 22 + Vn + p=8240° 14 & j4 R © 220° A -jsza solution: 22r- 22 1 + Va - ( 8440 + telee 0 000- 2 -j+ (1) 220° A # Concept L-M L₂-M iz -- iz li M

Applying above concept, the giren circuit can be redrawn as: I 212 jar tm Iz 22 jar + Voc (1,+12) (2-12) 8240 + 2 -je 7 7 6 2 20A Applying KUL in loop ④ : 8240 ☆ 介 (2+j3) I, - ; 4(1+ 12) =0 8240 = (2+j3 + j1) I, + j1 I, 2240 = (2+j4) I + j1 Iz 1 eq°(4) Applying KVL in loop ③ jul 1,+ 12 ) + (2 +j3) 12 - 1-j1) (2 - 12) = 0 ji I, + j4 In + 21, + j3 12 +2j – Inj - o js I, + Il je + j3+2 -j) +2y = 0 j1 I, + 12 (2 今 > 2 +j3) = -2;

22-90° = (j 1) I, + (2 +j3) Iz - eg" (2) conver- eq? (1) & eq? (2) into vesting corving eg polar equation: 8240 = (4.47263.43)3,+ (1290) I, 22-go = (1290) I, + ( 3.60 256.30) 12 above on eq?! solving 12= 9.329 278.450 15.23_121.595 12 = 0.6125Z-43.145' A Thus, Va can be expressed as = (2) (12) Vy((2) 20) (0-6/852-48148) V = 2 Von = 1.225L-43.145 v ANSWER...