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provide product for following mechanisms shown

1. NaOCH, 1. H, 2. heat حمله Page 1 of 4
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Answer #1

NaOCH3 gives OCH3- which is a strong base and it abstracts the most acidic proton.

Thereafter the anion(formed upon acid-base reaction in last step) undergoes SN2 reaction with given alkyl bromide.As this is SN2 reaction, so it will be favoured much at the position where least hindrance is present.During this SN2 reaction, the anion attacks (from backside) at the carbon to which least hindred bromine is connected.

Remember the configuration of dark bond(chiral carbon) will not change

step 1 T och Nat Š most acidic hydrogen BY -Br least hindered Step-2 Br LG •Br

After this ester hydrolysis takes place and ester is converted to carboxylic acid.

and Upon heating CO2 leaves.

Br ester hydrolysis OH 1110) Br tautomerisation lilia Final product به گم

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