Question

Determine the final pressure (in mm Hg) of a gas initially at a pressure of 395 mm Hg in a 3.47 L vessel at 25°C if it is transferred to a 1.24 L vessel at 100°C. a) 0.0153 mmHg b) 1.38 x 10 mmHg c) 1.82 mmHg d) 4.42 x 10 mmHg b

Answer 1

Answer = option B

1.38 * 10 mm Hg

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The pressure at changed volume and Temperature is determined by General gas Equation----

$\frac{P_{i}V_{i}}{T_{i}}=\frac{P_{f}V_{f}}{T_{f}}$

$P_{i}$ = Initial pressure of the gas

= 395 mmHg

$V_{i}$ = Initial volume of the gas

= 3.47 L

$T_{i}$ = Initial Temperature of the gas

=

= 298 K

$P_{f}$ = Final pressure of the gas

= ?

$V_{f}$ = Final volume of the gas

= 1.24 L

$T_{f}$ = Final temperature of the gas.

=

= 373 K

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$\frac{P_{i}V_{i}}{T_{i}}=\frac{P_{f}V_{f}}{T_{f}}$

$\frac{395mmHg*3.47 L}{298K}=\frac{P_{f}*1.24L}{373K}$

(4.5995 mmHg * 373)/1.24 = Pf

Final pressure of the gas = 1383mmHg

= $1.383*10^{3}mmHg$