Question

5. (a) A radio station broadcasts at a frequency of 91.5 MHz (1 MHz = 106 Hz). At a receiver some distance from the antenna, the maximum magnetic field of the electromagnetic wave detected is 2.10 x 10-11 T. (i) (2 pts) What is the maximum electric field of the electromagnetic wave at this receiver? (ii) (1 pt) What is the wavelength of the electromagnetic wave? (b) Sunlight strikes a piece of crown glass at an angle of incidence of 40.0° (i) (1 pts) What is the angle of reflection? I (ii) (3 pts) Calculate the difference in the angle of refraction between red (660 nm) and blue (470 nm) rays within the glass. The index of refraction is n = 1.512 for red and n = 1.524 for blue light (iii) (3 pts) The light now travels inside the glass. What is the minimum angle of incidence

Answer 1

As we ang their =) Fol с ( know, E = BC where Eo and Bo by Maximum value. of B = 2.1x10" 1 and Given, c =3x108m m/s to = BC = ( 2018 3)*16"xion 6.3x103 N/C He wavelength) ง 3x108 m/s = 3.28 m giosx106/ 6 incidence are related co through Snell's law : - sini hr Siny ni Crown glass (ng) = 1.517 no-1.517 Sin (40) 10512 --) Smoo) sing = sinho = sinho = 0.424 1.517 = 29.07 all here. 1 ) same (sing red - Sinuo 1. 512 = 0.425 -) ( 25.16 (Sing) bine Sinho 0.422 1.524 다. 00). blue = 24.95

(111) for for Internal reflection totally: Dair Singo nglass sini = --) smi- + + 512 = 0.6614 Aglass 41.405 This is minimum angle angle of incidence.