Question

15. The manufacturer's specification for torque on a SACH Foot Adapter is 398 in lb. What is this figure in the SI system (Nm) (6 points) (1 A-12 in) (1 m - 3.28 ft) (IN-0.2248 lb) 16. The Sub-Ischial Triangle modification has an area of .0059 mº. What does this convert to in English Units ( in) (6 points) (1 m - 100 cm) (1 in - 2.54 cm)
please show all steps. thank you.

Answer 1

Q15 To connect 398 in lbr into N-W, t. Ift & 12 in 2) Im= 3.28 tt IN = 0.2248 l by (given) from @ Im= 3.28ft → ift - m 3.2 from @ 12 in he (since I ft = 12 in) $3.28 1 in 1 m 3.28x12 from 6 IN 0.2248 lbr Ilbr-1 N 0.2248 Nm 398 = 398 in lbr 80, 3.28X12 0.2248 = 44.98 Nm. Q16 0.0059 m² to int Given : 1) Im = 100cm 2) lin = 2.54cm

from Im= 100cm from 2 1 cm = in. 2.54 So, from 0 Im= 100XL in in – 2.54 (3 Х So, 0.0059m? = 0.0059 Imxlm = 0.0059 X 100 100 (in) 2.54 (fean 6.0059m² To6. 35 6 in Ans, 2.54