Find the % mass of a 8.44 m solution of benzoic acid (C7H6O2) dissolved in acetone (C3H6O). The density of the solution is 1.19 g/mL.
Find the % mass of a 8.44 m solution of benzoic acid (C7H6O2) dissolved in acetone...
A student dissolves 14.g of benzoic acid C7H6O2 in 425.mL of a solvent with a density of 0.92 g/mL. The student notices that the volume of the solvent does not change when the benzoic acid dissolves in it. Calculate the molarity and molality of the student's solution. Round both of your answers to 2 significant digits.
When 0.3163 g of benzoic acid (C7H6O2) was dissolved in 15.563 g cyclohexanol, the freezing point of the mixture was 8.19 degrees C lower than that of the pure cyclohexanol. What is the molal freezing point constnt of the cyclohexanol? (delta T = m x Kf x i)
Benzoic acid, C7H6O2, occurs naturally in many berries. A 1.50-g sample of benzoic acid is combusted in a bomb calorimeter. The temperature of the calorimeter increases from 22.50 0C to 31.69 0C. The calorimeter contains 775 g water and has a heat capacity of 893 J/0C. Based on this information, how much energy (in kJ) is released when you metabolize 1.50 g of benzoic acid? The specific heat capacity of water is 4.184 J/(g⋅0C).
A chemistry graduate student is given 100 ml. of a 0.60 M benzoic acid (HCH.CO,) solution. Benzoic acid is a weak acid with K, 6.3x10 of KCH,CO, should the student dissolve in the HCH.CO, solution to turn it into a buffer with pH = 4.767 What mass You may assume that the volume of the solution doesn't change when the KC HCO, is dissolved in it. Be sure your answer has a unit symbol, and round it to 2 significant...
(a) Calculate the ratio of dissolved benzoic acid to benzoic ion that will exist in solution at equilibrium at pH of 2.00. The acid equilibrium constant (Ka) for benzoic acid is 6.46x10^-5. Note that this calculation doesn't account for the benzoic acid that has precipitated from solution, but you can assume that the higher the ratio, the more benzoic acid will precipitate. (b) Carry out the same calculation for a pH of 4.00, and explain why it was important to...
A student dissolves 11. g of benzoic acid (C,H,02) in 500 ml of a solvent with a density of 1.19 g/ml. The student notices that the volume of the solve does not change when the benzoic acid dissolves in it. Calculate the molarity and molality of the student's solution. Round both of your answers to 2 significant digits. molarity - O 0 0 0 molality - 0 x 5 ?
Benzoic acid has a molar mass of: 122.1 g/mole. What is the molarity of a benzoic acid solution in which 14.7 grams of solute are placed in 74.2 mL of solution. REPORT YOUR ANSWER TO 3 DIGITS DO NOT PUT UNITS IN THE ANSWER BOX Answer: -5 Benzoic acid is a weak acid with K = 6.46 x 10 What is the pH of a solution which has concentration: 0.580 M benzoic acid? REPORT YOUR ANSWER TO 3 DIGITS ACCURACY...
A. For the recrystallization lab, you had 1.0 grams of benzoic acid. What volume of water would it take to dissolve the sample at 100 °C given the solubility data below for benzoic aid in water? You cool the solution of the given volume of water from part a to 0 °C, what mass of benzoic acid remains dissolved in the solution and what mass precipitates out? b. If you then let the solution increase to 25 °C, what mass...
A chemistry graduate student is given 450.mL of a 0.70M benzoic acid HC6H5CO2 solution. Benzoic acid is a weak acid with =Ka×6.310−5. What mass of KC6H5CO2 should the student dissolve in the HC6H5CO2 solution to turn it into a buffer with pH =3.79? You may assume that the volume of the solution doesn't change when the KC6H5CO2 is dissolved in it. Be sure your answer has a unit symbol, and round it to 2 significant digits.
"calculations only" 1. How would you prepare a 25% m/m NaOH solution in methanol (CH3OH m.m =0.79 g/cm3). 2. How would you prepare a solution of 0.10 mole fraction of glucose (C6H12O6 ) in water? 3. Calculate the molarity and mole fraction of acetone in a 1.00 m solution of acetone (C3H6O) in ethanol (C2H6O). Density of acetone= 0.788 g/mL; Density of ethanol 0.789 g/mL. Assume volumes are additive.