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• A wall of an industrial oven consists of three different materials, as depicted in Figure. • The first layer is composed of
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SOLUTION ts K-0.08 Tu 13 T12 400°C h, 1001 Kaooth Wilmak K-0.72 ml/mak T6=30°c n=400/mk T2 w/make k5cm. Iscm * -10cm noo-30 alow finding Temperature 12 01 Rew 130.93 1, 12 (a) 129 130.03 = 400-12 You 1.3093 = 400-12 12,398.69°C now finding finding te348.83 = noo-14 tua simboc es finding nlow temperature 영 OT Rew 130.93= 15-16 Yuu 3.273,19-30 15 = 33.27°C

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