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Question 3 (20 points) (a) How many words with or without meaning, can be formed by using all the letters of the word, INSAN

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Answer #1

Answer:

a)

Given,

Word INSANITY

Here the word INSANITY has 8 letters with 2 I's , 2 N's & remaining were different

So,

Number of arrangements = 8! / (2!*2!*1!*1!*1!*1!)

= 8! / (2*2)

= (8*7*6*5*4*3*2*1) / 4

= 10080

b)

Given word TENNESSEE

Here the word contains 9 letters with 4 E's , 2 N's , 2 S's & 1 T

So, they can arrange in = 9! / (4!*2!*2!*1!)

= (9*8*7*6*5*4*3*2*1) / (4*3*2*1*2*2*1)

= 3780

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