Solve the following exact differential equation with initial value. (5x + 4y)dx + (4x - 8y3)dy = 0, y(0) = 2
Determine whether the equation is exact. If it is, then solve it. (4x®y+8) dx + (x4 - 5) dy = 0 Select the correct choice below and, if necessary, fill in the answer box to complete your choice. = C, where is an arbitrary constant. O A. The equation is exact and an implicit solution in the form F(x,y) = C is (Type an expression using x and y as the variables.) OB. The equation is not exact.
4. Solve the exact differential equation. (1-2xy)dx + (4y3 - x2)dy 0 4. Solve the exact differential equation. (1-2xy)dx + (4y3 - x2)dy 0
Problem 4. Verify that the differential equation is exact then solve it! (4x + 2y)dx + (2x + 4y)dy = 0 Answer:
Solve the exact differential equation (4 x y tsin x) dx + (x" - Y) dy = 0
The differential equation4xy²+6xy+(4x²y+3x²+1)dy/dx=0Has solutions of form F(x, y)=c whereF(x, y)= _______
solve the exact differential equation (-2sin(x)-ysin(x)+2cos(x))dx+(cos(x))dy=0 where y(0)=5
a) Consider the first-order differential equation (y + cos.r) dx + dy = 0. By multiplying integrating factor y(x) = ei" to both sides, show that the differential equation is exact. Hence, solve the differential equation. (6 marks) b) Solve the differential equation (4.r + 5)2 + ytan z = dc COSC (7 marks)
dy Find the solution of differential equation: dx - 4x2 = 4x°y(CER)
Solve differential equation. (x/y) (dx/dy) +(ln(y) - x) =0 I have been told it is not solved by substitution. It doesn't look exact or separable. It appears to be linear, but the mixed variable for qx and the natural log is confusing to me.