Question

Of 380 randomly selected medical students, 30 said that they planned to work in a rural community. Find a 95% confidence interval for the true proportion of all medical students who plan to work in a rural community.

What is the Z critical value?

What is the margin of error (E)?

What is the value of ^p?

What is the confidence interval?

Round all probabilities to three decimal places.

Answer 1

Given that n=380, x=30, The 957 Confidence interval for the true proportion of all medical studenty is p £ z pq The critical value of Zoos is 1.96 p=2 / 2 -0.0789 n 30 - n 380 pq 9=1-=0.9211 the margin of endaz (1-96) %6.0789] (0.9211 380 -0.0271 The confidence interval is 0.0789 +0.0271 :) 0.10518, 0.1060 (0.052, 0.106)