of 345 randomly selected medical students, 29 said that they planned to work in a rural community. find a 95% confidence interval for the true proportion of all medical students who plan to work in a rural community
Answer
sample proportion p(hat) = 29/345 = 0.084
sample size n = 345
z score for 95% confidence level is 1.96
confidence interval =
of 345 randomly selected medical students, 29 said that they planned to work in a rural...
Of 380 randomly selected medical students, 30 said that they planned to work in a rural community. Find a 95% confidence interval for the true proportion of all medical students who plan to work in a rural community. What is the Z critical value? What is the margin of error (E)? What is the value of ^p? What is the confidence interval? Round all probabilities to three decimal places.
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