Question

Question 3 1 pts Three conductors are involved in a measurement of capacitance. When conductor #1 and conductor #2 are connected together, the capacitance between them and #3 is 125 pF. When conductors #1 and #3 are connected, the capacitance between them and #2 is 125 pF. When conductors #2 and #3 are connected together, the capacitance between them and conductor #1 is 100 pF. Determine the mutual capacitances C12, C13, and C23. O C12= 75, C13= 75, and C23= 50 (all in pF). O C12= 75, C13= 50, and C23= 50 (all in pF). C12=50, C13= 50, and C23= 50 (all in pF). O C12=50, C13= 50, and C23= 75 (all in pF).

Answer 1

3) let 3 Conductors ere 1, 2, 3 Capacitance between 1925) Ciz 1993 >> (13 2 & 3 = C23 C13 (23 =) II Cea = (3+23 125 2 23 Cat C23 125 1 3 12 +43 = 100 2 3 adding 3 equations 90 C2+(23 +631) : 350 (12 + C234 C31 = 175 from azt 125 = 175 (12= 50 PF from (6) &d 175 125+ C13 : (13= SOPE

resonance tuency put C12, C3 in equation & in 50+ C23 + 50: 175 (23= 750F fourth option is Correct 12:50 (13=50, C23=75 PF 12) for Series RLG Circuit at 2T LC 20 J 106 100x1012 15.915 MHZ 16MHZ given statement true because at resonance frequency impedance minimum.