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B Consider the shaded region bounded by y=x2 – 4 and y= 3x + 6 (see above). Note that the r-axis and y-axis are not drawn to

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(9) and y= ² 4 y= 34 + 6 for A =0 21--2 for C, 21=0 put So, (21. y) = (-2,0) Au put y = 0–4=-4 (ny) = (0,4) Au intersection p(C) Wort y. and y = 3x + 6 y = n²4 Sy 21 = y-6 = n = +++ 3 y = - 4 to for right f = ly+4 y=0 left th= - 14+4 and 0 to 21 y =

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