Question

If the gain formula is applied for the sign flow diagram given in Figure 1 what happens to the input and exit relationship?

2 R(S) + 23 3 2- 2 workflow diagram

Answer 1

2 Solution R(3) + +7+ 23 2 43Tccs >ccs) + 2 xx २ २k M R(3) 423 २ 3 VA 4k V ROS) + X (3) 7 *3 २ M 8

Now making Signal Flow Graph a R(3) 93 3 Y lo 넌 Loop!- abc = 7x23x(+) = -161 Looba - abcde = 7x23x2x3*(-1)=-966 Loop 3 - bed = 23 x2x1 = 46 Loope - cde = 48 = 2x3x8 { PRAK = By Mason's Crain formala. G(3) = R(8) where k= no. of forward path Pk = the kth forward path gain 4-1-(E loop gains) + (E non touching loop gains two at a time) Ak 1-( loop gais which doesn't touch kthe fosward path) abcde) (1-0) 603) RCB T-Cabc tabcde+bed +cde)+(0) CO) 7x23x2x3x(1) 966 R(3) 1-(-161-966+46+48) 1034 4 Ams.

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