Question

Find the distance in nm between two slits that produces the first minimum for 400-nm violet light at an angle of 49.5°. X nm

Answer 1

given data

wavelength λ = 400 nm = 400x10^-9 m

angle  θ= 49.5^o

Order m = 0 ( for first minimum )

we know that

d sinθ = (m+(1/2)) λ

d = (m+(1/2)) λ / (sinθ )

plugging the values in the formula

d = (0+(1/2))(400x10^-9 m) /(sin49.5^o ) = 263.02 x10^-9m = 263.02 nm

d= 263.02 nm

distance between two slits is = 263.02 nm

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