Please fast back, i don't have more time
By entering the following equation in Wolfram alpha,
we get the solution as,
Simplifying we get,
Thus option (e) is correct.
Please fast back, i don't have more time The solution of the equation [ax? +(6+1)y2]dx -...
this question is only this The solution of the equation [ax? +(6+1)y2]dx– xydy=0, where a and b are constant is Select one: a. In(a+b ) = 2bln(x) b. (a+b)x2 + by2 = x26+2 c. ax? +by= c x26+2 O d. by2 = c x26+2 e. ax2 + y2 = 0 - 2bln(x)+c g. ax? +(6+1)y2 = C x26 +2 h. In(ax2 +by?)=2bln(x)+c
The solution of the equation [ax? +(+1)y2]dx - xydy=0, where a and b are constant is Select one: O O a. ax+(6+1)y2 = c X20 +2 b. (a+b)x2 +by2 = c x26+2 c. by2 = c x2b +2 d. ax? +by2 = c x26+2 O O O en( - ) - - 2bumba) + 6 o f. ax? +by2=C O g. In(ax2 + by2)=2bln(x)+C a info o *) – 2016)
The solution of the equation [ax? +(6+1)y?]dx - xydy=0, where a and b are constant is Select one: o a. ax2 + by2=C x26 +2 o b. ax2 +(6+1)y2 = c X20 +2 o - - 2bln(x)+c o d. (a+b)x2 +by2 = C x20 +2 O ein(a+b*) - 2 O f. In(ax+by?) = 2bln(x)+c o g. by2 = c x2b +2 h. ax?+by2 = 0
The solution of the equation [ax?+(+1)y?]dx - xydy=0, where a and b are constant Select one: O a. by2 = x26+2 b. (a+b)x2 + by2 = x26+2 c. ax+by2 = c x25+2 о O a. Infatb = = 2bln(x) X4 O e. ax2 + (6 +1)y=x26+2 of. In(ax?+by2)=2bln(x)+C o g. ax?+by2=c - 2bln(x)+c
The solution of the equation [ax+(6+1)y?]dx - xydy=0, where a and b are constant is Select one: o a. ax? +(b + 1)y2 = C x26 +2 o b. (a+b)x2 + by2=C x26+2 oc. by2 = C x26+2 o d. ax? +by2 = C x26+2 eina- ok 2 ) = -2 -2bln(x) + c o f. ax2 +by2=C O g. In(ax2 + by2)=2bln(x)+c y² O = 2bln(x) n. Infato )
The solution of the equation [ax' +(6+1)y?]dx-xydy=0, where a and b are constant is Select one: a. ax?+by2 = c o amfotok) - 20 = 2bln(x) c. (a+b)x² + by2 = c x26+2 d. I = - 2bln(x)+ c e. In(ax? + by?) = 2bln(x)+c f. ax2 + by2 = c X26+2 g. by2 = c x26 +2 h. ax? +(6+1)y? = < x26+2
Please fast back, i don't have enough time The solution of the IVP dy - (ax + by+1)2-1(0)=0, where a ER and b ERYO) 15 Select one: e a. (ax+by + 1)(1-x) = 1 2 b. (ax+by+1) (ax+by+1)1 -bx) = di ax+by 1 e Cax+by+1211 -bx)= 1 1. (ax+by- 1)(1-x)=1 Cox+by+1)(1+x)=1 hax+by+1)(1-bx)= 3
The solution of the equation [ax? +(6+1)y?]dx– xydy=0, where a and b are constant is Select one: O a. ax” +by? =C b. nlatok 3) = 2 = 2bln(x) o cby? = x26+2 O d. ax? +by? = cx20 +2 e (a+b)x?+by? = x22 o fax +(6+1)/2 = c x2 +2 og Inax? +by?)=2bin(x)+c = -2bln(x)+c
Please fast back, i don't have enough time If y=x+ is the general solution of ++ dy = (y - x)2 +1, then the function vis dx Select one: 1 a. X + C-X b. X 1 O c.x²+. c-x² O d. x²+c ex+c 1 f.X+ с+х 8.-x+c O h.c
Please fast back, i don't have enough time if a and are constants, the solution of Cayev+b)dx + 2ye WV + axy?owy - 1)dyo is Select one: O aye w+bx=y b.yo"4bx+y=c ce + bx-c od yox-y-c Oye "+bx-y-c oo"+bx-y=0 gye "+bx-y=c hyle-1)=0