Please fast back, i don't have enough time
Please fast back, i don't have enough time The solution of the IVP dy - (ax...
Please fast back, i don't have enough time if a and are constants, the solution of Cayev+b)dx + 2ye WV + axy?owy - 1)dyo is Select one: O aye w+bx=y b.yo"4bx+y=c ce + bx-c od yox-y-c Oye "+bx-y-c oo"+bx-y=0 gye "+bx-y=c hyle-1)=0
Please fast back, i don't have more time The solution of the equation [ax? +(6+1)y2]dx - xydy=0, where a and b are constant is Select one: a. Infa+b ) - 2010 2 bin(x) ob. (a+b)x?+by2.cx20 +2 c.inlano) -- 2blnly) +6 d. ax? +(+1)/2 = c X25+2 e. ax? +by2 = cx20 +2 Of. by2 = cx25+2 g. In(ax2 + by2) = 2bin(x)+c 0 h, ax² + by=0
The solution of the IVP dy dx = (ax+by+ 1)2 - ; y(0)=0, where a ER and b ERVO) is Select one: a. (ax+by+1)(1 + bx)= 1 2 b. (ax+by+1)= 1-bx c. ax + by=1 d. (ax +by+1)(1 - bx)2 = 1 e. (ax+by-1)(1 - bx)= 1 f. (ax+by+1) (1 - bx)= 1 g. (ax +by+1)(1-bx)= 1 h. (ax+by+1)(1 - bx)=3
Please fast back, i don't have enough time a + If a ER-1) and b ERX1}, the solution of x dy dx y a +1 1-b is 1-b Select one: a.yl-=X+c+xa O b. y = x+c+xa-1 ocyl-b=x+cx- O d. y-b = x+c+x4 o eyl-=C+xa f. y 5=x+c 8. y = x+c+x 0 h. y - 1= x1+x
Flag question Marked out of 6.00 Question 1 dy The solution of the IVP = (ax+by+1) where a ER and b ERVO) is bi y0)=0, Select one a. (ax + by - 1)(1-x-1 b. (ax+by+1)(1+x)=1 clax+by + 1) (1 -bx=1 dax+by = 1 lox+by+1 (1 -bx) = 1 2 Olax+by+1)- 1-bx (x+by+ 1X1 - bx) = 3 (ax+by+ 1X1 -bx) = 1 Ne
The solution of the IVP dy dx = (ax+by+112 - 8 yO=0, where a ER and b ERVO} Select one: O a. (ax + by + 1) (1 + bx)=1 O b. ax +by=1 O c.(ax +by+1) (1 - bx)=1 o d. (ax+by-1 (1-bx)= 1 2 O e. (ax+by+1)= 1-bx of. (ax +by+1)(1-bx)2 = 1 O 8. (ax +by+1)(1-bx)=1 oh. (ax +by+1)(1 - bx)=3
Please fast back, i don't have enough time If y=x+ is the general solution of ++ dy = (y - x)2 +1, then the function vis dx Select one: 1 a. X + C-X b. X 1 O c.x²+. c-x² O d. x²+c ex+c 1 f.X+ с+х 8.-x+c O h.c
The solution of the IVP dy dx (ax +by+12-6: YO)=0, where a ER and b ERVO) is Select one: a. ax+by=1 b. (ax+by+1)(1-bx)= 3 c. (ax+by-1)(1-bx) = 1 d. (ax+by+1)(1-bx)2 = 1 e. (ax+by+1)(1 - bx)= 1 2 f. (ax+by+1) = 1- by o g. (ax +by+1) (1 - bx)=1 n. (ax +by+1)(1+bx)= 1
The solution of the IVP dy dx = (ax+by+1)2 - Ø; y(D)=0, where a ER and b ERVO) is Select one: a. ax+by=1 b. (ax+by+1)(1-bx) - 3 c. (ax+by-1)(1 - bx)= 1 d. (ax +by+1)(1 - bx)2 = 1 e. (ax+by+1)(1-bx)= 1 2 f. (ax+by+1)= 1-bx g. (ax+by+1) (1 - bx)= 1 h. (ax+by+ 1)(1+bx) = 1 O O
The solution of the IVP dy dx = (ax+by+1)2 – 6; y(0)=0, where a € R and b ERVO} Select one: a. (ax +by+1)(1+x)= 1 O b. (ax+by+1)(1-x)=3 O c. (ax+by+1)2(1 - bx)=1 2 O d. (ax +by+1)= 1- bx e. (ax+by+1)(1-bx)= 1 of. (ax +by+1) (1 -bx)2 = 1 о g. (ax +by-1)(1-bx) = 1 O h. ax + by=1