The solution of the IVP dy dx = (ax+by+1)2 – 6; y(0)=0, where a € R...
The solution of the IVP dy dx = (ax+by+ 1)2 - ; y(0)=0, where a ER and b ERVO) is Select one: a. (ax+by+1)(1 + bx)= 1 2 b. (ax+by+1)= 1-bx c. ax + by=1 d. (ax +by+1)(1 - bx)2 = 1 e. (ax+by-1)(1 - bx)= 1 f. (ax+by+1) (1 - bx)= 1 g. (ax +by+1)(1-bx)= 1 h. (ax+by+1)(1 - bx)=3
The solution of the IVP dy dx = (ax+by+1)2 - Ø; y(D)=0, where a ER and b ERVO) is Select one: a. ax+by=1 b. (ax+by+1)(1-bx) - 3 c. (ax+by-1)(1 - bx)= 1 d. (ax +by+1)(1 - bx)2 = 1 e. (ax+by+1)(1-bx)= 1 2 f. (ax+by+1)= 1-bx g. (ax+by+1) (1 - bx)= 1 h. (ax+by+ 1)(1+bx) = 1 O O
The solution of the IVP dy dx (ax +by+12-6: YO)=0, where a ER and b ERVO) is Select one: a. ax+by=1 b. (ax+by+1)(1-bx)= 3 c. (ax+by-1)(1-bx) = 1 d. (ax+by+1)(1-bx)2 = 1 e. (ax+by+1)(1 - bx)= 1 2 f. (ax+by+1) = 1- by o g. (ax +by+1) (1 - bx)=1 n. (ax +by+1)(1+bx)= 1
The solution of the IVP dy dx = (ax+by+112 - 8 yO=0, where a ER and b ERVO} Select one: O a. (ax + by + 1) (1 + bx)=1 O b. ax +by=1 O c.(ax +by+1) (1 - bx)=1 o d. (ax+by-1 (1-bx)= 1 2 O e. (ax+by+1)= 1-bx of. (ax +by+1)(1-bx)2 = 1 O 8. (ax +by+1)(1-bx)=1 oh. (ax +by+1)(1 - bx)=3
Flag question Marked out of 6.00 Question 1 dy The solution of the IVP = (ax+by+1) where a ER and b ERVO) is bi y0)=0, Select one a. (ax + by - 1)(1-x-1 b. (ax+by+1)(1+x)=1 clax+by + 1) (1 -bx=1 dax+by = 1 lox+by+1 (1 -bx) = 1 2 Olax+by+1)- 1-bx (x+by+ 1X1 - bx) = 3 (ax+by+ 1X1 -bx) = 1 Ne
The solution of the equation [ax?+(+1)y?]dx - xydy=0, where a and b are constant Select one: O a. by2 = x26+2 b. (a+b)x2 + by2 = x26+2 c. ax+by2 = c x25+2 о O a. Infatb = = 2bln(x) X4 O e. ax2 + (6 +1)y=x26+2 of. In(ax?+by2)=2bln(x)+C o g. ax?+by2=c - 2bln(x)+c
The solution of the equation [ax' +(6+1)y?]dx-xydy=0, where a and b are constant is Select one: a. ax?+by2 = c o amfotok) - 20 = 2bln(x) c. (a+b)x² + by2 = c x26+2 d. I = - 2bln(x)+ c e. In(ax? + by?) = 2bln(x)+c f. ax2 + by2 = c X26+2 g. by2 = c x26 +2 h. ax? +(6+1)y? = < x26+2
The solution of the equation [ax? +(6+1)y?]dx - xydy=0, where a and b are constant is Select one: o a. ax2 + by2=C x26 +2 o b. ax2 +(6+1)y2 = c X20 +2 o - - 2bln(x)+c o d. (a+b)x2 +by2 = C x20 +2 O ein(a+b*) - 2 O f. In(ax+by?) = 2bln(x)+c o g. by2 = c x2b +2 h. ax?+by2 = 0
Please fast back, i don't have enough time The solution of the IVP dy - (ax + by+1)2-1(0)=0, where a ER and b ERYO) 15 Select one: e a. (ax+by + 1)(1-x) = 1 2 b. (ax+by+1) (ax+by+1)1 -bx) = di ax+by 1 e Cax+by+1211 -bx)= 1 1. (ax+by- 1)(1-x)=1 Cox+by+1)(1+x)=1 hax+by+1)(1-bx)= 3
The solution of the equation [ax? +(6+1)y?]dx– xydy=0, where a and b are constant is Select one: O a. ax” +by? =C b. nlatok 3) = 2 = 2bln(x) o cby? = x26+2 O d. ax? +by? = cx20 +2 e (a+b)x?+by? = x22 o fax +(6+1)/2 = c x2 +2 og Inax? +by?)=2bin(x)+c = -2bln(x)+c