Question
please help i will rate
Write the structure of the Michael addition product and the final Robinson annulation product when using the following starti
0 0
Add a comment Improve this question Transcribed image text
Answer #1

oct 11 Na o Et be Go por I Ceton OG og H ort - H I CHO CH 111 O= C-H I X O= C M micheal addition product Scanned with CamScan16 goat Go Naded H- H La rh GO Eton Oct n=0 Le con H G Doet t Hoc OHC Nao Et atoh Woer Cyclisetim OHC Онс Eto-H Pout Naoct Et

Add a comment
Know the answer?
Add Answer to:
please help i will rate Write the structure of the Michael addition product and the final...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • Write the structure of the Michael addition product and the final Robinson annulation product when using...

    Write the structure of the Michael addition product and the final Robinson annulation product when using the following starting materials.* The dialdehyde is the Michael donor and the ketone is the Michael acceptor. Will rate and comment, thanks! *PLEASE IDENTIFY THE STRUCTURES OF MICHAEL ADDITION AND FINAL ROBINSON ANNULATION PRODUCT Н. Michael addition product Robinson annulation product

  • SUPPLEMENTAL QUESTION 4 (10 pts) Write the structure of the Michael addition product and the final...

    SUPPLEMENTAL QUESTION 4 (10 pts) Write the structure of the Michael addition product and the final Robinson annulation product when using the following starting materials. Hint: the dialdehyde is the Michael donor and the ketone is the Michael acceptor. H. Н Michael addition product Robinson annulation product

  • Write the structure of the Michael addition product and the final Robinson annulation product when using...

    Write the structure of the Michael addition product and the final Robinson annulation product when using the following starting materials. Hint: the dialdehyde is the Michael donor and the ketone is the Michael acceptor. H ze Michael addition product Robinson annulation product

  • please help me solve both of these!! Write the complete stepwise mechanism for the acid catalyzed...

    please help me solve both of these!! Write the complete stepwise mechanism for the acid catalyzed hydrolysis of the compound shown. Show all intermediates, indicate with curved arrows the movement of electrons and show all formal charges and lone pairs of electrons where relevant. Write the structure of the Michael addition product and the final Robinson annulation product when using the following starting materials. Hint: the dialdehyde is the Michael donor and the ketone is the Michael acceptor. Н Michael...

  • Draw Michael addition product and the final Robinson annulation product. These are starting materials, Н. Н....

    Draw Michael addition product and the final Robinson annulation product. These are starting materials, Н. Н. о о о

  • 1. A Robinson annulation is a reaction that involves: (i) a Michael addition of an enolate...

    1. A Robinson annulation is a reaction that involves: (i) a Michael addition of an enolate onto an ,ß-unsaturated enone followed by (ii) an intramolecular aldol reaction. The molecule shown below (cyclohexenone X) can be made through two different Robinson annulation reactions. (A) Show the two different sets of starting materials (i.e. ketone 1 &a,p-unsaturated enone 1 and ketone 2 & a,B-unsaturated enone 2) for each Robinson annulation. Draw the reagents/reaction conditions. (B) Then pick one set and draw an...

  • Max Eldabbas Rahul Mehta Nikitha Menon So Jung Park loseph Pitts Aamir Siddiqui Michael Uhle Stev...

    help solving circled ones Max Eldabbas Rahul Mehta Nikitha Menon So Jung Park loseph Pitts Aamir Siddiqui Michael Uhle Steven Van Osten abe cde 96 97 a 48 49 50 Alexa Vander Ploeg bde afh 96 97b 48 49 50 abd aef 96 97b 48 49 50 bod bdg 96 97 a 48 49 50 bce fgh 96 97a 48 49 50 abe ghf 96 97b 48 49 50 ade ace 96 97 48 49 5o cde def 96 97b...

  • 1. draw the structure of the product of the enamine formed between cyclohexanone and morpholine 2....

    1. draw the structure of the product of the enamine formed between cyclohexanone and morpholine 2. draw the structure of the Michael addition product 3. draw the structure of the final product This question has multiple parts. Work all the parts to get the most points. The Stork reaction is a condensation reaction between an enamine donor and an a,B-unsaturated carbonyl acceptor. The overall reaction consists of a three-step sequence of 1. formation of an enamine from a ketone, 2....

  • 5.) 5 the goldd reach Section 2 Pro 32. A B-keto ester is a product in...

    5.) 5 the goldd reach Section 2 Pro 32. A B-keto ester is a product in which of the following reactions? A) Aldol condensation B) Claisen condensation C) Dieckmann condensation D) Robinson annulation E) Michael addition Section 17-13 33. An a,ß-unsaturated ketone is a product in which of the following reactions? A) Aldol condensation B) Claisen condensation C) Diekmann condensation D) Robinson annulation E) Michael addition Section 17-11 addition when mixed with base?

  • 10. Please Check 1 by 1 and read carefully. I would need a perfect score for...

    10. Please Check 1 by 1 and read carefully. I would need a perfect score for this . Thanks Select the keyword or phrase that will best complete each sentence A Claisen reaction is a nucleophilic substitution in which an enolate is the nucleophile Key terms: Robinson annulation Aldol condensation: An aldol reaction in which the initially formed p hydroxyl carbonyl compound loses water by dehydration. Claisen reaction Aldol condensation Dieckmann reaction: An intramolecular Claisen reaction of a diester to...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT