An object is placed 10.0000 cm in front of a lens with focal length =-19.0000cm. Where...

Question

Question

Answer 1

Answer #1

(1/u)+(1/v)=1/f

u=object distance =10cm

v=image distance=?

f=focal length=-19

(1/u)+(1/v)=1/f

(1/10)+1/v=1/(-19)

1/v=(-1/19)-(1/10)=-29/190

v=-190/29= -6.55cm=image distance

Answer 2

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