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An object is placed 15 cm in front of a divergent lens whose focal length is 12 cm. Where would the image be located (in cm)?

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DELIAL n . Cobject distance from te = ? given U = -15 cm Everging lens focal length = - 12 cm by lens formula ū 12 V - 15 7Values are taken negative because...all the values are in left...side.....so by sign convention all values will be negative....towards left....& Positive towards right

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