An object is placed 100cm in front of a lens of focal length 50cm. A lens...
An object is placed 100cm in front of a lens of focal length 50cm. A lens of focal length -20cm is placed 90cm beyond the first lens.
a) Where is the final image located?
b) Is this a real or virtual image?
c) What is the magnification of the lens combination?
d) Is the final image inverted or upright?
e) Is the final image bigger or smaller than the object?
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An object is placed 100cm in front of a lens of focal length
50cm. A lens...
2) (20 pts) A lens of focal length +20cm is placed 50cm to the left of...
2) (20 pts) A lens of focal length +20cm is placed 50cm to the left of a mirror of focal length 40cm. An object is located 60cm to the left of the lens (follow sign conventions). A) (10 pts) for the intermediate image: i) What is the image distance (relative to the lens)? ii) What is the magnification? iii) For each of the following, circle the answer that describes the quality of the image: Real / Virtual Upright / Inverted...
1.) An object is placed in front of a diverging lens with a focal length of...
1.) An object is placed in front of a diverging lens with a focal length of 17.7 cm. For each object distance, find the image distance and the magnification. Describe each image. (a) 35.4 cm location _____cm magnification _____ nature real virtual upright inverted (b) 17.7 cm location _____ cm magnification _____ nature real virtual upright inverted (c) 8.85 cm location _____ cm magnification _____ nature real virtual upright inverted 2.) An object is placed in front of a converging lens...
a) Suppose an object is placed 7.50cm from a converging lens with a 5cm focal length....
a) Suppose an object is placed 7.50cm from a converging lens with a 5cm focal length. Use ray tracing to get the image and measure image distance. Describe the image: (upright or inverted, real or virtual, bigger or smaller). b) Use the lens equations to calculate the location of the image and its magnification. Describe the image: (upright or inverted, real or virtual, bigger or smaller).
(a) An object is placed 7.5cm from a converging lens having a 5cm focal length. Use...
(a) An object is placed 7.5cm from a converging lens having a 5cm focal length. Use ray tracing to get the image and measure image distance. Describe the image from your drawing (upright/inverted, real/virtual, bigger/smaller). Please use ruler to get as accurate as you could (b) Use the lens equations to calculate the location of the image and its magnification. Describe the image from your calculation (upright/inverted, real/virtual, bigger/smaller).
An object is placed 24.1 cm in front of a convex mirror of focal length 50...
An object is placed 24.1 cm in front of a convex mirror of focal length 50 cm. Note: Do convex mirrors have a positive or negative focal length? What is its image position? Answer in units of cm. The magnification of the image in the previ- ous question is: With the arrangement discussed above, the image is: 1. virtual, inverted, smaller than object 2. real, erect, smaller than object 3. real, inverted, bigger than object 4. real, erect, bigger than...
a small object is placed 25.0 cm from a converging lens of focal length 40.0cm.the object...
a small object is placed 25.0 cm from a converging lens of
focal length 40.0cm.the object is to the left of the lens where is
the image?
same as the previous question. which statement is true about
the image?
It is real, upright and larger than the object It is virtual, upright and larger than the object. It is virtual, inverted and larger than the object. It is virtual, inverted and smaller than the object. It is real, inverted and...
An object is placed 6.0 cm in front of a lens of focal length 5.0 cm....
An object is placed 6.0 cm in front of a lens of focal length 5.0 cm. Another lens of focal length 4.0 cm is placed 2.4 cm behind the first lens. (a) Where is the final image? distance cm location ---Select--- behind the second lens in front of the second lens, but between lenses in front of the first lens Is the image real or virtual? virtualreal (b) What is the overall magnification?
A small object is placed 25.0 cm from a converging lens of focal length 40.0 cm....
A small object is placed 25.0 cm from a converging lens of focal length 40.0 cm. The object is to the left of the lens. Where is the image? A- 17cm to the right of the lens B- 25cm to the left of the lens C- 17 cm to the left of the lens D-25 cm to the right of the lens E-67cm to the right of the lens F-67 cm to the left of the lens A small object...
(5%) Problem 3: An object is placed between the focal point and the front of a...
(5%) Problem 3: An object is placed between the focal point and the front of a concave mirror, as shown. The focal-point locations are indicated by the small black circles. 50% Part (a) Which diagram best represents the image location and magnification for the original object? E 는 1 O - A 50% Part (b) Which choice best describes the image? The image is virtual, upright, and smaller than the object. The image is virtual, inverted, and smaller than the...
An object is placed 14.0 cm in front of a lens of focal length 5.08 cm....
An object is placed 14.0 cm in front of a lens of focal length 5.08 cm. Another lens of focal length 4.48 cm is placed 1.83 cm past the first lens. Where is the final image (how far past the lens with focal length 4.48 cm)? 2.59 cm You are correct. Your receipt no. is 158-1618 Priwinuti Tiit Is it real or virtual? Incorrect The image is virtual Correct: The image is real You are correct. Your receipt no. is...
2) (20 pts) A lens of focal length +20cm is placed 50cm to the left of a mirror of focal length 40cm. An object is located 60cm to the left of the lens (follow sign conventions). A) (10 pts) for the intermediate image: i) What is the image distance (relative to the lens)? ii) What is the magnification? iii) For each of the following, circle the answer that describes the quality of the image: Real / Virtual Upright / Inverted...
(a) An object is placed 7.5cm from a converging lens having a 5cm focal length. Use ray tracing to get the image and measure image distance. Describe the image from your drawing (upright/inverted, real/virtual, bigger/smaller). Please use ruler to get as accurate as you could (b) Use the lens equations to calculate the location of the image and its magnification. Describe the image from your calculation (upright/inverted, real/virtual, bigger/smaller).
a small object is placed 25.0 cm from a converging lens of
focal length 40.0cm.the object is to the left of the lens where is
the image?
same as the previous question. which statement is true about
the image?
It is real, upright and larger than the object It is virtual, upright and larger than the object. It is virtual, inverted and larger than the object. It is virtual, inverted and smaller than the object. It is real, inverted and...
A small object is placed 25.0 cm from a converging lens of focal length 40.0 cm. The object is to the left of the lens. Where is the image? A- 17cm to the right of the lens B- 25cm to the left of the lens C- 17 cm to the left of the lens D-25 cm to the right of the lens E-67cm to the right of the lens F-67 cm to the left of the lens A small object...
(5%) Problem 3: An object is placed between the focal point and the front of a concave mirror, as shown. The focal-point locations are indicated by the small black circles. 50% Part (a) Which diagram best represents the image location and magnification for the original object? E 는 1 O - A 50% Part (b) Which choice best describes the image? The image is virtual, upright, and smaller than the object. The image is virtual, inverted, and smaller than the...
An object is placed 14.0 cm in front of a lens of focal length 5.08 cm. Another lens of focal length 4.48 cm is placed 1.83 cm past the first lens. Where is the final image (how far past the lens with focal length 4.48 cm)? 2.59 cm You are correct. Your receipt no. is 158-1618 Priwinuti Tiit Is it real or virtual? Incorrect The image is virtual Correct: The image is real You are correct. Your receipt no. is...
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