Question

a small object is placed 25.0 cm from a converging lens of focal length 40.0cm.the object is to the left of the lens where is the image?

same as the previous question. which statement is true about the image?

It is real, upright and larger than the object It is virtual, upright and larger than the object. It is virtual, inverted and larger than the object. It is virtual, inverted and smaller than the object. It is real, inverted and larger than the object. It is real, inverted and smaller than the object.

Answer 1

lens ù conver with focal length for wovention f = Here minus sign lills that the left side Ao the converging t = 4000 cm calculations By sign = +40cm By uns equation t. 1-/ f u= - 25.0cm f V и f th / It 40 (-25) ch s tel 40 کی فی 3 2 ť = 25-40 40X25 40825 40x5 vz 2 = -66.660 67 cm 3 image u on e I lens.

As we the can see that image is on the ref g here the image is virtual magnification of object given by We know that will be As v=-200/3 matv U2-25 by sign conversion and calculations 200 3 25 & 2.6667 As eml> so, the image i magnified As we know that the magnification is also given by me hi ho m is positive AS no hi will be positive of course ho is positive by sign convention so , alternatively hi is positure image is upright So the Correct option is 2