Question

Given the following circuit, find the voltage V3, of the circuit, if element A is

10 Ω 20 Ω 20 V S 60V A 1, 40 Ω + 30 Ω"

a) A short circuit

b) An independent 9V voltage source, with the positive reference on the left

c) A dependent current source, with the arrowhead to the left and marked 5i1.

Answer 1

sol til 20v gou IA 60V itiz 2 402 + 3or VA go 202 = IA 20 (eti,)-(1+iz) current through the 4or = ع -6 4on 2012 - 40(1-12) - 0 3012 - 401, +4012 o -401, + 7012 noastaa -60+ (loin) 20 (1) + 3012 = O. 101, +3012 = 80 2 8 = 2.94A 1.68 A solve ① & ② (1,-12) x4on - V3 1402 400 50.4 V

b nou 901 20V lusti 1200) av f 60v Liz+190n) 12 nou 30 VB -20 –9 +12on120)=0 ison 29 a 1.45A. 20 Чол - 1.45 +i, -liq+1.45) iinia s 0 +9+ ivor (UO) – 3012 401,-40iq-3012 9 401, 2012 2 -60 + 10i, - 90 (1.45).+ 30 12 = 101, 43012 = 89 solue ① & ② =3.13A, 19 = 1.92A Y? =(1-12) 40 = (3.13-1,92) x40 =48.44 Vg = 48.4 V

lor e) 20V 20~ Siniz 51,-iq+i, 6i-12 t sii Gor ya -ie Wor 901 N3 KUL'A 20(51,-12) --20 +40 (1,-12)-3012 = 0 looi 2012 +401,-4012-3012 = 20 1401,-9012 - 20 0 -60 + 101, - 20(51,-iz) + 3012 = 60 10 i, -1001, + 2014 + Boia _909, +5012 = 60 solve ia ..9.27 A i = -5.818A V3 =(liriz) 40 Vg =( -5.818 +9.27.)*40 V3 = 138.08 V