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6) Proteins are composed of amino acids polymerized into long chains. The structure of a protein - that is, its overall shape

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Answer #1

Hi!

Let's discuss thermodynamics.

So, folded or unfolded, what is the difference in energy?

In the folded structure we are told that there is an order in the structure, the hydrophilic functional groups get exposed and the hydrophobic ones "hidden" as facing the interior of the protein and interacting with the other hydrophobic residues. This is a response to the media since the protein is in a hydrophilic environment.

So, for entropy you know is associated with possibilities of rearrangements that have the same energy. If the structure was unfolded the water and ions that surround it could take more configurations whereas in the folded one the water has a designated place to be as we say "order" we mean less configurations available, more structured configuration. So the folded structure will have much less entropy than the unfolded one.

About enthalpy, we have that the folded structure has lower energy, is more stable. Because of the interactions, hydrophobic is interacting with hydrophobic; and hydrophilic with hydrophilic. This interactions contribute to lower the energy whereas in the unfolded structure we'll have repulsive interactions or weaker interactions. So DH would be negative if we go from unfolded to folded and positive if we go from folded to unfolded.

You know that positive DH means endothermic reaction, so it makes sense that when we heat the protein it unfolds.

For B, we'll use Van't Hoff's equation:

ln(\frac{K_{T1}}{K_{T2}})= -\frac{R}{DH}*\left ( \frac{1}{T_{1}}-\frac{1}{T_{2}} \right )

K_{t}=\frac{folded}{unfolded}

and the percentages are then Kt . 100 so remember to divide by 100.

ln\left ( \frac{0,82}{0,4} \right )= -\frac{8,314J/Kmol}{DH}*\left ( \frac{1}{(30+273)K}-\frac{1}{(5+273)K} \right )

DH= 3, 43.10-3 J/mol

Hope to have been helpful!

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