Question

A long steel (SAE 1018HR) plate is welded on both ends as shown in the following figure. The plate thickness is 10mm. The dimensions shown blow are b = 50mm,d = 25mm,c = 200mm, h = 5mm. A concentrated force F is applied at the center. The electrode material is E7010. A factor of safety is assumed to be 2.5 for both plate and welding. Find the maximum allowable force F. F О hv d ki b

Answer 1

We have t = 10 mm b = 50 mm d = 25 mm 200 mm h = 5 mm F.O.S = 2.5 Draw А Diagram b = 50mm 5 사 म d IMA C С 25 mm RA lo this welded plate the force acting ( Due to Symmelic R. R А B 2 From table

Permissible tensile Stress Sheak 440 MPa 220 MPa 0 1 440 F.O.S 11 440 2.5 = 176 MPa a S = 0 = 176 MPa YA L 11 T ys 220 Fos 88 MPa 2.5 88 MPa G = Su ys Also R R & R А 2 transverse weld Find R = 10.709xhub 12 10. 107 X 5 X 50 X176)x 2 - R 62216 N R = 62216

Parallel weld 2x pxчx LOE 0 3 IT 0.707 X 5 X25 X88 7777 N 7777 N so beauty above uba R 62216 + 7777 69993 N А R 69993 N A Also Here F = Fmax R = 5 - F max 2x 69993 139986 no - F 139.986 KN a mare