Problem 3 A block accelerates at a constant rate down a long inclined ramp. The coefficient...

Question

Question

Problem 3 A block accelerates at a constant rate down a long inclined ramp. The coefficient of kinetic friction between the b

Answer 1

Answer #1

from the figure

let the total distance is x

x = vi*t+1/2*a*t^2

here acceleration = a

from the figure

ma = mgsin40- $\mu$ mgcos40

a = 9.8sin40- $\mu$ *9.8cos40 = 6.301- $\mu$ 7.51

x = 1/2(6.301- $\mu$ 7.51)*10^2 = 315.05- $\mu$ *375.5

at the 5 sec

speed vf = ( 6.301- $\mu$ 7.51)*5 = 31.505- $\mu$ *37.55

for last 5 sec

200 = (31.505- $\mu$ *37.55)*5+1/2*(6.301- $\mu$ 7.51)*5^2

200 = 236.2875- $\mu$ *281.625

$\mu$ = 0.129 (answer for part B)

length of the ramp

x = 315.05-0.129*375.5 = 266.61 m (answer for part A)

Answer 2

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