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A 500-kg block is placed on highest end of a 50° ramp that is 50-m long...

A 500-kg block is placed on highest end of a 50° ramp that is 50-m long and it immediately starts to slide down hill. Identify all the forces acting on the block and then determine total amount of work done on the block if it travels all way to the bottom of the ramp.
The static and kinetic coefficient of friction are μs= 0.4 μk= 0.4 respectively.

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Answer #1

all the forces acting on the block - Frictional force and force due to gravity

So, net force acting on the block = mgsin50 - ukmgcos50

                                                     = 500 * 9.8 * sin50 - 0.4 * 500 * 9.8 * cos50

                                                    = 2493.75 N

=> total amount of work done on the block =   2493.75 * 50

                                                                     = 124687.5 J

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