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Problem 8 Part A Find the average power delivered to the 5 k2 resistor in the circuit of (Figure 1). Suppose that Vin = 235 Z

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Griven circuit NiN2 25:1 NN2 1:50 20012 m d 5U vin 2in1 Zin 2 Zin! (N2 2L zin ZL --> load yozistance N2 INI =) secondary s p2008 II m 1.2542 vin zin- Vin = min 1.4542 1.25 +0.22 I = 235 20° 1. 45k I 162,068 MA VI Iso 1.25u2 n20 2.5 Volts General for:: V = VI (2) V2 - 2025 e 8.10 Volts Socond ratio V3 12 - N2 NI N2 - 8.10 V2. V3 10 (59) ( V3 405,17 volts I3 = V3/5k J3 = 81:: V = VI (2) V2 - 2025 e 8.10 Volts Socond ratio V3 12 - N2 NI N2 - 8.10 V2. V3 10 (59) ( V3 405,17 volts I3 = V3/5k J3 = 81

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