x= Jy=X Show that | * (x+3y) dy dx = [ { « + 3) dx dy + m2 L); *+ 3ydr dy (x + 3y) dx dy + (x + 3y) dx dy Jy=1 Jx=y2
Integrate and evaluate the given equation 4. x dy dx + 3y = 3
Find the general solution of the following: x dy/dx +3y =x^3 -x y=?
there is no error it is not limit! x= Jy=X Show that | * (x+3y) dy dx = [ { « + 3) dx dy + m2 L); *+ 3ydr dy (x + 3y) dx dy + (x + 3y) dx dy Jy=1 Jx=y2
Evaluate ∫C(2x - y) dx + (x + 3y)dy C: arc on y=x5/2 from (0, 0) to (4, 32) _______
(2x+ 2 x y²) dx + ( x ²) - 3y) dy = 0 solve your equation
The solution of the differential equation X dy dx – 3y = x sin2x + x4-4x5 is y - "Cos2x = *sin2x+*+-2x + cx True False
Find the general solution for the differential equation. x dy/dx + 3y = 4x2 – 3x; x>0 y=_______
Find dy/dx by implicit differentiation. -7xy + 3y - 7 = 0 7[***] - 7y(x + 1)
Use Euler's Method to approximate y(0.5) given dy/dx=3x-3y with y(0)=3 and delta x=0.1.