Integrate and evaluate the given equation
where C is constant of integration
4. x dy dx + 3y = 3
x= Jy=X Show that | * (x+3y) dy dx = [ { « + 3) dx dy + m2 L); *+ 3ydr dy (x + 3y) dx dy + (x + 3y) dx dy Jy=1 Jx=y2
Evaluate ∫C(2x - y) dx + (x + 3y)dy C: arc on y=x5/2 from (0, 0) to (4, 32) _______
5. Evaluate the integral c (2x -y)dx + (x + 3y)dy along the path C: line segment from (0,0) to (3,0) and (3,0) to (3,3) 5. Evaluate the integral c (2x -y)dx + (x + 3y)dy along the path C: line segment from (0,0) to (3,0) and (3,0) to (3,3)
Calculus 3 Evaluate SOLVE NUMBER 30 Evaluate x2 dx dy (x + 4y3) dx dy x + 4y dx dy cos(2x + y) dy dx e-3x-4y dy dx
The solution of the differential equation X dy dx – 3y = x sin2x + x4-4x5 is y - "Cos2x = *sin2x+*+-2x + cx True False
Find the general solution for the differential equation. x dy/dx + 3y = 4x2 – 3x; x>0 y=_______
8. Evaluate $c (4xy3 + 3y) dx + (8x – 6x?y?) dy where C is the triangle formed by vertices (0, 0), (3,0), (3, 4) oriented counterclockwise
(2x+ 2 x y²) dx + ( x ²) - 3y) dy = 0 solve your equation
Find the general solution of the following: x dy/dx +3y =x^3 -x y=?