Question

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Part A In a balanced three-phase system, the source is a balanced Y with an abc phase sequence and a line voltage Vab = 215Z 55°V. The load is a balanced Y in parallel with a balanced A. The phase impedance of the Y is 5+3j 12/0 and the phase impedance of the A is 3-9 12/0. The line impedance is 1.4+0.83 12/9. Use the single phase equivalent circuit to calculate the line voltage at the load in the a-phase. Express your answer in volts to three significant figures. Enter your answer using angle notation. Express argument in degrees. View Available Hint(s) VAX 1 vec ? VAB V Submit

Answer 1

Given data Vab : 215 L55'v (1-1) (Y) - 5+j3^/ph . Phase impedance of Y connected load phase impedance of a load 3-jq s/ph The line impedance 1.4 +0.8 rlph 1•4+30.8 a A * A Пstјз- (3-jan 215/55°v 3-jgn n 1.4 +30.8 5+j31 S+ј3л S B < 3-jq~ 1,4+2018 Converting stor RY 3-j9 =(1-j3). 3 215_55 124:13 L55' v. Van Vab 53 As the toad is "Balanced considering per phase equivalent 14+jo8 A circuit A a T :124013 U5v sus stjan 1-із n. Zealph (<5+j3) //(-j3))+(+4+308) = 3.92141-17-8189 ((5 +j37] 01-13) : Van. - 124013 4550 X Zea CS Scanned with CamScanner

:. VAN 97-28 (32-218 v : VAB 3X VAN 0 168.494 232.216 CS Scanned with CamScanner