Question

3- a balanced three-phase Y-Y system, the source is an abc sequence of line voltages is Vab - 300230 V rms. The line impedance per phase is 0.6 +j1.22, while the per-phase impedance of the load is 10 +j1492. The line currents in A is: (a) 9.342 - 25.1 (b) 16.182 - 25.1 (e) 6.232 - 55.1 (d) 3.112 - 25 (b) For the circuit in Fig. the inductor current 1() is (a) 6 A (b) 10 A (c) 4 A (d) O A 10 A

choose the correct answer

Answer 1

0.6 p2j 3oolo Vabr 300230 2 0 2120 0,6 1,2j 0.6 1.2 j phase voltage of star - source, Upn = 300 Lo per phase equivalent circuit is A 300 Lo es Scanned with (016+ 1120)+(10+141) CamScanner

To = 300320 (10,6 + 15.2 TA = 9.34 Z-55.1 E A TOA 21 54 E30 o At to Ilth Br inductor is shart arcuited YA 10 Olt=0) = - A to | Ilt-) = co worent cauflow 0 only in Short circuit branch Uzob