Questions cover CLOS Question 3 In a balanced three-phase wye-wye system, the source is an abe-sequence set of volt...
1. In a three-phase balanced wye-wye system, the source is an abc-positive sequence set of voltages with Van- 120 20 Vrms. The per phase impedance of the load is 5 +j62. If the line impedance per phase is 0 Ω, find the line currents, the line to line voltages at the source, and the line to line voltages at the load 120 20 Vms 2. In a three-phase balanced wye-wye system, the source is an abc-sequence set of voltages with...
In a three-phase balanced wye-wye system, the source is an abc-positive sequence set of voltages with Van = 120 000 Vrms. The per phase impedance of the load is 5 +J60. If the line impedance per phase is 0 0, find the line currents, the line to line voltages at the source, and the line to line voltages at the load. 1. Van 120 0" Vrms ZY = 5+j Va VA neutral
508 CHAPTER 11 . POLYPHASE CIRCUITS 11.40 In a balanced three-phase system, the source has an aboc phase-sequence and is connected in delta. There are two rallel wye-connected loads. The phase impedance of load i and load 2 is 4 The line impedance connecting the source to the loads is 0.3 + j0.2 2. If the curre IAN! = 10/20-Arms, find the delta currents in the source 4 Ω and 10 +/4 Ω, respectively. nt in the a phase of...
A balanced positive-sequence wye-connected 60-Hz three-phase source has line-to-line voltages of VL = 440 V rms. This source is connected to a balanced wye-connected load. Each phase of the load consists of a 0.5-H inductance in series with a 50-Ω resistance. Assume that the phase of Van is zero. home / study / engineering / electrical engineering / electrical engineering questions and answers / A Balanced Positive-sequence Wye-connected 60-Hz Three-phase Source Has Line-to-line Voltages ... Question: A balanced positive-sequence wye-connected...
(15 points) In a balanced three-phase wye-delta system, the source has a positive (abc) phase sequence and a phase voltage of Van 200VrmsZ - 30°. If the line impedance is zero and the line current is LaA -6ArmsZ- 65°, find the load impedance per phase in the delta. AB AB Arms
A wye-delta balanced three-phase system with a positive phase sequence has negligible line impedance and a load impedance of Z, = (12+j8) 12. If LAB=14.42286.31° A-rms, determine the line currents and the source voltages.
Sketch the 3-phase systems, and show your calculations: Problem (a): A positive-sequence balanced thrcc-phase wyc-connected source supplics powcr to a balanced wyc-connected load. The line voltage is 100 V. The line impedance is 2 ? per phase, and the load impedance is 50 +j30 ? per phase. Determine the load voltages if V an-00. Problem (b): A positive-sequence balanced three-phase wye-connected source supplies power to a balanced wye-connected load. The magnitude of the line voltages is 208 V rms. If...
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A balanced, positive-sequence, wye-connected source has V- 220/0 V rms and supplies an unbalanced wye-connected load ZAN-7 10 Ω, ZBN-8 +j6 Ω, and ZCN 10-j12 Ω via transmission lines with impedances ZA-2 +jl Ω, ZB-2-j0.5 Ω, and ZC-2 +j | Ω (a) Label all node voltages and loop currents (b) Determine the currents IaA? IbB, and 1cC. (c) Determine the voltages VAN, N, and VCN (d) Determine the voltages VAR, VRc, and VCA (e) (i) Determine the total...
1.) For a balanced three-phase wye-wye circuit. For a negative or ‘acb' sequence, SOURCE с LOAD a + Van n 5k b If Van = 100 VAC (effective voltage) a. Find the other phase voltages, Von and Vcn, including phase angles. b. Find the Line Voltages, including phase angles. C. If Zy = 5k12, find the magnitude of the phase and line currents. note: review the notes from Wednesday/Thursday on which measurements are phase, line, voltages and currents.
In a balanced three-phase system, the source is wye-connected and the source voltage of phase A is Van = ∠ 120 20 V. The load consists of two balanced wyes in parallel with phase impedances of 8 + j6 Ω and 12 + j8 Ω. If the line impedance is zero, find the line currents and the phase currents in each load. (Hint: use per phase analysis, then do angle shift for each phase.)