Question

Two ships leave a port at the same time. The first ship sails on a bearing of 35° at 24 knots (nautical miles per hour) and the second on a bearing of 125 at 28 knots. How far apart are they after 1.5 hours? (Neglect the curvature of the earth.) After 1.5 hours, the ships are approximately nautical miles apart. (Round to the nearest nautical mile as needed.)

Answer 1

the one are two legs of we will find the ist ship's trajectory and the and ship's trajectory actually from a right angle; since Leaves 350 and one leaves 195, which 90 a part. The ships trajectories are the afore legs of a right triangle. If we find the hyph the nuos hyph the nuos of the right traingle after 1.5 hours distance but the two ships · after 1.5 hos, the st ship has gone 1-5 (24) - 36 nautical miles The second ship has gone 1.5 (38) = plug a= 36 and b = 42 into the phythagodean the oven to solve for the hypho thu se ic ug² -42 nautical mile sol 362 + c?, 1996+ 1764 3060 C-3060 C: 13060 (-55-3172) nautical miles a pagt.