Question

Question 9 4 pts In one city 51.1% of adults are female, 10.2% of adults are left handed, and 4.7% are left handed females. Find the probability that an adult selected at random is female or left handed. Type your answer in the box. Don't type the sign.) 0613 Question 10 9 pts The following contingency table shows the joint frequency distribution for votes cast in a presidential election by region and political party Answer each with a simplined fraction or as a decimal to three decimal places Political Party Demo Repub. Other Total Regon PL Ps NE 9046 11,336 101 20.483 R: MW 10,511 14.761 169 25.441 R s 10,998 17.699 136 128,833 RS w 7022 10,659 214 17,895 B4 Total 37,577 54,455 620 92.652 Find the probability that a randomly selected voter a) is a Democrat given that they live in the NE blives in the south given that they are a Republican 614 is a Democrat

question 9 and 10 thanks on advance !

Answer 1

Sol a) from the given information, P(female) = 0.511 P(left handed) = 0.102 P (left handed AND female) = 0.047 Here, we need to find P(female or left handed) = P(female) + P (left handed) - P(female AND left handed) = 0.511 + 0.102- 0.047 0.566 10) a) Here, we need to find P(Democrat I live in the NE) P (Democrat AND live in the NE) 11 P(live in the NE) 9046/92652 - 90 46 20483/ 92652 = 0.4416345262 20483 0.442

b) Here, we need to find P(lives in South) Republican) P (lives in South AND Republican) P (Republican) 17, 699/92,652 54,455 | 92652 17,699 0.3250 20659 54, 455 O. 325 c) 37577 Pl Democrat) 92652 0.40557138 0.406