Question

UID Iz 2 47? 33. Rewrite the equation x2 - 6x - 11 = 0 in graphing form by completing the square. Give the location of the vertex. Use graphing form to solve for x (look for two solutions and don't forget to simplify into simplest radical form). 34. An exponential function goes through the points (2, 2) and (-3, 64). Find the equation of this function. Show all work.
questions 33 and 34

Answer 1

Solution! 33 Given x²-6x-11=0 2 Converting the ginen equation in graphing from x² - 6x-11-0 = (22 – 2x3x + 33-32-11 - 0 (x-3)2 - 9-11=0 = (x-3)²_20=0 for an?+ 6x + 6.0 (x-h7 ²+k a (nik) Here Vertex = (3,-20) loction verted comparing Now, (x-3) -20 = 0 (x-3)2 = 20 (2-3) (2-3) = I 245 二土 +(2012 (4xs)" =423/12.5'2 -) x = 3 I 255 Henry and x= 3 +255 = 3-255 Am

.. girm by where a = initial value Exponentia fonesia -x 2. a. 62 and 64 .-3 E a b 42=ax Solution : 34 Exponential function General form is Fin) = a.lt b= growth/ decry factor let f(n) = a.bh be an exponential function parses through print (2, 2) and (-3,64) Answer ? then we can write, ffn) = 8(2) dividing By 115 b = (5) = 16 = 1 2 hr at for a=82 6=1/2 ax(+1²= ។ Exponential frutian & a= 2x4=8 [a=8 fim) -- 811334 - 6,1% fon) fos = 8 (2) ² 32 64 bu & 6-3 ab2 =) 32 2 3 ) 65 こ . 32 =) YN 2 from o 2=as² z 22 Ary