Question

A balanced 30, delta load, draws a phase current of 9 Arms from a 600Vrms, 30 source. What is the total apparent power (in kV

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Answer #1

Given Data:

Phase Current = 9 Arms

Rms Voltage=600Vrms

Rms Voltage convert to Phase Voltage= 600/\sqrt{3}

Phase Voltage = 346.41 V

Apparent Power(in KVA)= Phase Voltage x Phase Current

= 9 x 346.41

= 3117.69 VA

Apparent Power(in KVA) = 3.1 KVA

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