Question

Python code that Returns a COPY of string s1 with every instance of old_char in s1 replaced by new_char

Answer 1

Thanks for the question. Below is the code you will be needing. Let me know if you have any doubts or if you need anything to change. 

Let me know for any help with any other questions.

Thank You!

===========================================================================

def replace(s1, old_char, new_char):
    s1_copy = ''
    for letter in s1:
        if letter == old_char:
            s1_copy += new_char
        else:
            s1_copy += letter
    return s1_copy


def main():
    s1 = input('Enter a string: ')
    old_char = input('Enter the character you like to replace: ')
    new_char = input('Enter the character you like to replace with: ')

    print(replace(s1, old_char, new_char))


main()

==================================================================

1: Proj 1 2 3 def replace (31, old_char, new_char): 31_copy = for letter in sl: if letter == old_char: 31_copy += new_char else: 31_copy += letter return sl_copy 5 7 8 9 10 11 12 13 def main(): sl = input ("Enter a string: ') old_char = input ("Enter the character you like to replace: ") new_char - input('Enter the character you like to replace with: ') 14 15 16 print (replace (81, old_char, new_char)) 17 main() 19 20 Run: 1. Z: Structure replace() > for letter in s1 > else 7282020.ax C:\Users\User\PycharmProjects\Analytics\venv\Scripts\python.exe C:/Users/Use Enter a string: Hello world! Enter the character you like to replace: 1 Enter the character you like to replace with: t Hetto Wortd! IᎵ ; Process finished with exit code 0 * 2: Favorites . 4: Run 6: TODO Python Console > Terminal