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A wire 2.80 m in length carries a current of 10 A in a region where a uniform magnetic field has a magnitude of 0.78 T. Calcu
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Answer #1

sel l 2.80 m. ㅍ IOA = 0.78 T :B 120° & NB Il sin a FB then het N = 1 FB 180.78X 10x 2.8 X sin 120 18.91 N FB correct option.

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