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can someone please give detailed explanation in long hand form so that I can double check my work.

Answer all questions in the space provided for each problem, label all parts show equation, substitution (with units), and an

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Answer #1

The given details are

R1 = 10 ohm

R2 = 15 ohm

Supply Voltage , V= 5 V

The resistors are in series

(a) The total resistance

R = R1 + R2

R = 10 + 15

R = 25 ohm

(b) The total current in the circuit

By ohms law

V = IR

Current, I = V/R

I = 5/25

I = .2 A

(c) Total power supplied by the battery

P = VI

P = 5 * .2

P = 1 watt

(d) Voltage across the 10 ohm resistor

That is voltage drop in 1o ohm resistor

VR1 = IR1

   VR1 = .2 *10

VR1 = 2 V

(e) The given details are

Length of the wire , L = .5m

Current through the wire, I= 3 A

Magnetic field, B = .02 T

Given that current and magnetic field are perpendicular

that is  \Theta = 90o

magnetic force due to a current carrying wire is given by

F = ILB sin\Theta

F = (3*.5*.02) sin90o

F = .030 N

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