Question

Name Date Period Kuta Software Solving Systems of Equations by Substitution Solve each system by substitution. 1) y=6x-11 2) 2x - 3y = -1 -2x - 3y =-7 y=x-1 3) y=-3x + 5 5x - 4y=-3 4) -3x – 3y = 3 y=-5x-17 5) y=-2 4x - 3y = 18 6) y = 5x - 7 -3x - 2y=-12 7) y=-3x - 19 5x + 8y = 0 8) y = 5x - 3 -x + 7y=-21

Answer 1

Answer to the above Question is given below:

DATE 2 - 2. их - Зу 18 у = - 2 (ii) Чx-3y . 18 From equation (?), we get Sulistituting yo-d in equation ci) их - Зу е 18 - 6 18 их - 3(-2) 2 ) 8 Чx+ 6 = 18 Чу Чx 12 х3 12 ч xe 3 х = 3 Неге dhe y2-2 is the solution of alioue equcetion - Premium

DATE 6) Y = 5x - 7 - 3x - 2yz - 12 y = 2 58 - 7 - 3x-2y -12 Foam equatiou ci) we get 7 y z 5x 7 Sulistituting y = 5x - 7 iu equation tiis - 3x-2y - 12 -3x - 2 (5x-7) - 12 -3x - 10x + 14 = -12 - 13x z-12-14 - 13 x 2 - 26 Xz+26 +13 X z 2 Now put nalue of x=2 un equation (2) y 25%-7 y = 5(2) yz 107 1.3 Hence, Xz2, y = 3 is the solution of the alioue equatiou Premium

DATE Y у -3x - 19 5x + 8y y=-3x - 19 (t) 5x+8yo Fo4 ou aquaticau (1) We 9 get yz -3X - 19 Sulistituting y=-3x - 19 iu equatiou (ii) 5x+8yo 5 X + 8 (-3x -19), 58 - 24x-152 = 0 - 19 x zot 152 - 19 x = 152 X = 152 - 19 X-8 Now put malue of x z- 8 in equation is Y у -3x - 19 y = -3(-8) 19 Y 24-19 [y25 Hence, X²-8 2 y 25 is the solution of the alioue equation. Premium

DATE -3 8) Y 2 5x - -X +7 y = -21 y = 5x-3 -x+7Yz-21 lii) Fou equation (i), we get y = 5x-3 Sulistituting y = 5x-3 in equatiou (ii) - X +7 y = -21 -x + 7 (5x-3) -21 -x + 35x212-21 34 x z-21 +21 34 X zo Χιο 34 X 0 Nawe put malue of a zo in equation (8) у z 5X-3 y = 5(0)3 y = 0-3 Hence, X z o. is the solution of the allove equation. y=-3 3+ Premium cose

DATE Answell :- 1 y z 6x-11 - 2x-3y z - 7 y = 6x - 11 (i) 2-7 - (ii) 2x-3y Foom equation (i) we get y z 6 x - 11 Substituting y z 6X - || in equation (ii) - dx - 34 2 - 7 -2x - 366X-11) z 7 -2x - 18x + 33²-7 - 20x = -7 -33 720x740 208 2 uo 40 20 X х Now put the malue of x in equation (i) Y = 6 X - 11 Y z 6(2) 11 12 - 11 t y Z1 X z 2 9 Hence the is the solution of alone équation. Yz1 Premium

DATE 2) 2x - Зу = - 1 y = x 2 х - 1 2х - зу = -1 2 х - 1 Fй алм адабали (dі) , we aut у = х - 1 Sulistitutiug y = x-1 cm equation (1) 8 x - Зу = -1 x - 3 (x-1) - 1 - 3х + 3 2 - 1 - х 2 - 1 - 3 + X 2 + ч 1 х 2 ч Nous put #u wаku 6 х ц ім гаи аtіолл (ii) Y ч у х - 1 - 1 2 3 НО is the solution 2 X.u, 13 alique equation - b Premium

DATE 3) Yz 2-3x + 5 5x - 4y = -3 y=-3x + 5 li) () 5x - 4y =-3 FuL om equation (1) we get yz - 3x + 5 Sulistituting y=-3x+ 5 in equation (11) 5x - 4y 2-3 5 X-4 (-3x + 5) z -3 5x + 12x - 20 z-3 17 * = -3 + 20 17X z 17 X z 17 17 X Х z 1 Nowe put value of xz1 in equation e) 2 yz - 3x + 5 3(1) +5 -3+5 ca Hence 7 X = 1 Y 22 us the solution of the ali ove equatioú. 34 Premium

DATE 4 - 3x - 3y z 3 Y = -58 - 17 -3x-3y = z 3 (i) (ii) Y = -58-17 Fulam equatiou (ii) 2 we get Y у 2-58-17 Substituting yz -5x - 17 in equation lé) - 3x - 3y 23 - 3X-31-58-17) = 3 3x + 15 X + 51 : 3 12x z 3-51 12x -48 x z-48 12 x z-u Now put malue of x 2-4 in equation (ii) y z 5x-17 Y z-564) - 17 ya +20-17 of Hence , x 2-4, y =3 is the solution above equation ithe Bat Premium