Question

20: Solve the system of equations using substitution method. 2x+5y=26 X+ y= 10 21: Solve the following equation. x-x1/2-6= 0 22: Solve the following system of equations, using elimination method. 2x+3y = 5 5x- y = 4 23: Solve the system of nonlinear equations. Any Method. Y?=x2-9 2y= x-3 24: Convert the log into exponent form. Ln (3x-5)2= 16 25: f(x)= 1/x in words explain the transformation of the following functions. a. g(x) = 1/ (x-3) +5 b. h(x)= -1/(x+2) -4

Answer 1

1201. 2x + 5y = 26 xty from egh (11) х+у= lo Put 1o-X in eqh () 2x + 5 (10-x) = 26 2x + 50 - 5x - 26 → - 3x 26-50 - 3x = -24 → [x = 8 in eqn (ill), Putting x=0 y = 10-8 fy:2 therefore x=8 = 2 Anso 21. x - X LL WW x = t. t - t - 6 = 0 x - 3t +2t - 6=0 > t ( t - 3) + 2 (+ 3) = 0 → It-3) (t+2) = 6

(23) y² = x² - 9 2y = x-3 from egh (11) Putting yo X-3 2 in egn (1). (x-312 x²-9 x2 +9 - 6x = 4x2 – 36 3x2 + 6x 45 =0 x² + 2x - 15 = 0 x² + 5x -3x - 150 II+5) -311+5) :D x+5) (-3) = 0 -> 2+5=0 x = -5 X-30 = 12:3 Now, put values of in eqh (111) for x = -5 -5-3 2 -4 for x = 3 3-3 2 Therefore solutions x = -5 / y = – 4 x = 3 y=0 + Ang

(24). In (3x - 5)² = 16 2. In (3-5) = 16 In (3x - 5) 16 2 In (32-5) = 8 > (3x - 5) = e Ant 1251 f(x) = 1 / 1 (0) f (x-3) X-3 shifting to right by 3 unit} 3 +5 & shitting upward by 5 unit's +(x-3) +-5 X-3 g(1) = +5 (x-3) (6) f(x) = 24 + (x+2) = x+2 { shifting lett by 2 unit? { taking image about x- axi - f (x+2) (x+2) - f(T+2) - 4 - -4 (x+2) shifting downward by 4 unit hal (x+2)