1 Total cost $ 1215.24 0.97X + Lilly On Solving Li_d (7) 1215.24 un) we get X = Gummy bear y sol units & 657 units Chocolate bur CS Scanned with CamScanner
2 20 ounce 20 Let 'x' wnits of Energy Pebbles & byl units of Rice cake should be given. (mit = Ounce) Total qty (1) X Х- ну Energy Pettle contain 85% & Rice luke hus emergy. Totul should be 45% sugar. (857.) + 157.) y = (x+y) 45% :, 0.851 + 0,05% 20x45% . 1) , get X = Energy lebbles 10 Pebble=10 ounce Y = Rice Cake 5%. G t. - 10 ounce CS Scanned with CamScanner
3 (a lome Repo Fixed est = $35, variable cost = $5/hr fost function Fixed est + Variable cost . Clt) 3.5 + 5t i ; t in hrs. -) Tool time fixed cost $50, Variable Gst = $ 2/hr. Clt) 50 + 2t li) (6) subtruct ii) from lii) we get = (50-35) + (2-5)+ > 15 t both has 34 - shnd clt) = 35+5 (5) = $60 (c) The solution point (t, c(t)) = (5,60) shows the in difference point ie at this point same charge ( Total cost) which is $ for (d) Home Repo is ih euper if 1) < (0) vie 35+ 51 < 50 + 21t) 3t T 15 tx 5 hrs. ielif hrs. <5 cs Scanned with CamScanner
h Let it sold Bubble lop bubble gum 6x unit sold lyn units of Tooth Rot gum. & it total 260 li) X ty 2 bo Then sold aty i.e Cost of the Bubble pop & cost of tooth not Gst $ 271.75 1.2 X t o. 95 y $1.2 lunit $0.95/ unit Total 271-75 - زارا ۔ CS Scanned with CamScanner
On solving li) & (i), we get X = 99 qa, Y = 161 He sold Bubble Pop ? a 9 writs L & Tooth rot 161 units 5 (a) Cost Fixed Gst + Variable est Fixed Gst = $ 1650 & Variable = $35) necklace C(x) = 1650 + 35x]; x being no. of w neck laces. Reven ne per neck lnce & $85 16) o', li) (c) RIX) 85X on solving li) & li je Y = (1x) Y ч R(x) = 1650 +35X >X - 33 necklaces Graphical solution » 85X Break even 2-> CS Scanned with CamScanner
-3000 (33, 2805) C(x) = 1650 + 35 x 20000 R(X) + 85 x 1000 -10 10 20 30 40 50
6 at Let school store sold 6 x unit of gummy bear ost of $0.97 euch . & byl units of chocolate bur at cost of $1.11 each. Total sold sold qty 1158 X. ty У 1158 vi) CS Scanned with CamScanner