How many milliliters of 0.120 M NaOH are required to titrate 50.0 mL of 0.0998 M hypochlorous acid to the equivalence point? The Ka of hypochlorous acid is 3.0 × 10-8.
moles acid = 0.0500 L x 0.0998 = 0.00499 = moles NaOH
V = 0.00499/ 0.120 = 0.0416 L >> 41.6 mL
How many milliliters of 0.120 M NaOH are required to titrate 50.0 mL of 0.0998 M...
14. 35.00 mL of a 0.30 M HCl solution is titrated with 0.35 M NaOH. What is the pll of the solution after 28.00 mL of the NaOH has been added? (show your calculation steps) - 15. How many milliliters of 0.120 M NaOH are required to titrate 50.0 mL of 0.0998 M hypochlorous acid to the equivalence point? The Ka of hypochlorous acid is 3.0 x 10-8. (show your calculation steps)
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