solve neatly on paper step by step
solve neatly on paper step by step For the state of stress shown, (a) Solve for...
PROBLEM 7.82 - 100 MPa Solve Prob. 7.81, using the maximum-shearing-stress criterion. PROBLEM 7.81 The state of plane stress shown occurs in a machine component made of a steel with oy = 325 MPa. Using the maximum-distortion-energy criterion, determine whether yield will occur when (a) o = 200 MPa, (b) o = 240 MPa, (C) 00 = 280 MPa. If yield does not occur, determine the corresponding factor of safety.
Question # 2 110 marks t45 MPa For the state of plane stress shown in the figure: a Construct Mohr's circle (4 marks), b- Determine the principal stresses (2 marks), Determine the directions of principal planes (2 marks), d- Determine the maximum shearing corresponding normal stress (2 marks). a-80 MPa C- stress and the
For the given state of plane stress, calculate the strains on
each faces. (E=200 GPa, G=70 GPa, and v=0.3). a) Calculate the
principal strains and angle ?? at which it occurs. b) Calculate the
maximal shear stress in the plane and angle ?? at which it occurs.
(Hint; You can construct Mohr’s Circle for strain transformation
with the same rules as we constructed in stress
transformation)
80 MPa 40 MPa 50 MPa
Please use Mohr's circle to solve this
problem.
For the state of stress shown, determine the value of Txy for which the maximum shearing stress is 79 MPa. (Round the final answer to two decimal places.) 70 MPa ty 120 MPa The value of w is ± MPa
Q2. The state of stress on the surface of part of an engineering component is shown in Fig. 22. 94 MPa 51 MPa 25° 63 MPa Fig. Q2 - The State of Stress on the Surface of an Engineering Component (a) Using graph paper construct a Mohr's Stress Circle for the element and hence determine the magnitudes of the principal stresses and orientations of the principal planes. Clearly label these features on your diagram and sketch the state of stress...
2 Figure 1 shows the stress state of an element. Determine: a) The average and maximum shearing stress magnitude. b) Draw and label the orientation of the element such that the shearing stress is equal to zero. 1 compa 40 mPa. 8ompa. Figure 1
QUESTION 2 [10 marks! For the state of stress shown it is known that the normal and shearing stresses are directed as shown in Figure 2 and that 0,- 63 MPa, 0, -42 MPa and try = 28 MPa. Based on the information given, compute; 42 MPa 28 MPa 63 MPa Figure 2 (a) (b) the orientation of the principal planes. the principal stresses. 15 marks) (5 marks) QUESTION 35 marks The beam shown in Figure 3 is roller supported...
Q1. [15 Marks] The stress field in a thin flat structural member can be described by the following equations: Ox 20x + 30xy2 + 20y Oy = 30x2 – 50xy + 20 Txy = 20x – 100y? 02 = Txz = Tyz = 0 where (x, y, z) are in metres and the stress components are in MPa. a) Determine the body forces required to support the structural member in equilibrium; [2 marks] b) Draw a 2D stress element at...
Please solve this question clearly and step by step.
Thank you
2. A truss assembly shown in Figure Q2 below is made of aluminum alloy that has a modulus of elasticity, E = 69 GPa. member is 225 mm2 The cross sectional area of each 4300 N (0, 40) m (40, 40) m 2 500 N 3 (0, 0) FIGURE Q2 Determine the global stiffness matrix for the truss assembly. a. [10 marks] Determine the displacement at node 3. b....
Question 15 (1 point) A material element is subjected to plane stress conditions. The stresses at the point of interest are as follows (units of MPa are assumed): 0x =-87 Oy =36 Txy =-77 Determine the normal strain in the z-direction, Ex, in microstrain (to one decimal place). So if the value is 18.4 E-06, just enter "18.4". You may assume Young's modulus is 72 GPa and Poisson's ratio is 0.3 for this material.